(5x+7)(x^2+3x-4)=0

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Solution for (5x+7)(x^2+3x-4)=0 equation: 


Simplifying
(5x + 7)(x2 + 3x + -4) = 0

Reorder the terms:
(7 + 5x)(x2 + 3x + -4) = 0

Reorder the terms:
(7 + 5x)(-4 + 3x + x2) = 0

Multiply (7 + 5x) * (-4 + 3x + x2)
(7(-4 + 3x + x2) + 5x * (-4 + 3x + x2)) = 0
((-4 * 7 + 3x * 7 + x2 * 7) + 5x * (-4 + 3x + x2)) = 0
((-28 + 21x + 7x2) + 5x * (-4 + 3x + x2)) = 0
(-28 + 21x + 7x2 + (-4 * 5x + 3x * 5x + x2 * 5x)) = 0
(-28 + 21x + 7x2 + (-20x + 15x2 + 5x3)) = 0

Reorder the terms:
(-28 + 21x + -20x + 7x2 + 15x2 + 5x3) = 0

Combine like terms: 21x + -20x = 1x
(-28 + 1x + 7x2 + 15x2 + 5x3) = 0

Combine like terms: 7x2 + 15x2 = 22x2
(-28 + 1x + 22x2 + 5x3) = 0

Solving
-28 + 1x + 22x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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